JEE 2018 :: Physics (2018) :: Solved questions 2018

• Physics (2018) - Solved questions 2018

For an R-L-C circuit driven with a voltage amplitude v_m and freqency $\omega_{0}=\frac{1}{\sqrt{LC}}$, the current exhibits resonance. The quality factor, Q is given

Answer:

Explanation:

Sharpness of resonance of a resonant L-C-R Circuit is determined by the ratio of resonant frequency with the selectivity of circuit. This ratio is also called "Quality Factor" or Q-factor.

Q-factor = $\frac{\omega_{0}}{2\triangle\omega}$

$\frac{\omega_{0}L}{R}$

$\frac{I}{\omega_{0}CR}$

• Physics (2018) - Solved questions 2018